how to pass a dataset value in API as a string parameter ?
Schema "Quote"
https://www.mockaroo.com/schemas/149602
API
https://www.mockaroo.com/virtual_services/10169
If you see the schema ,status field is dataset and i want to pass the status in API
e.g.https://my.api.mockaroo.com/quotes.json?key=XXXX&status=Submitted
the above eg API will give me the records whose status is Submitted
Harish,
I am unable to access your schema "Quote" but I think I understand what you are trying to do. If you are wanting to use an URL parameter as the value to a column then you should use the following.
Schema: https://www.mockaroo.com/10be7960
Contains a field, Status that is of Formula type. The formula being used is request_params['status']
The Mock API url looks like this: https://my.api.mockaroo.com/3118.json?key=xyxyxyxy&status=Completed
Result:id,Status
1,Completed
2,Completed
3,Completed
4,Completed
5,Completed
6,Completed
7,Completed
8,Completed
9,Completed
10,Completed
Hope that helps you out.
Thanks for the reply ,and i got your point but I want the status column to be dataset so that when i pass the status Submitted in the API then it matches the values in dataset and then give me the records.
If I add request_params['status'] then anything/dummy can be passed.
Harish,
Ahhhh, I see what you are trying to do. Let's see if this helps you out -
Schema: https://www.mockaroo.com/10be7960
DataSet:
status,type,value,price
Submitted,Foo,Good,5.00
Cancel,Bar,Negative,0.00
Exception,Cookie,Excellent,100.00
Mock API: https://my.api.mockaroo.com/3118.json?key=xyxyxyxyx&status=Cancel
Response:
Cancel,Bar,Negative,0.00
The schema is where you will need to perform the from_dataset() function.
Thanks,
Rich
Thanks a ton..! It worked.
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So I got schema with 2 fields: id and name
I sending API call like that:
schema "v2"
data = generate 1
data['name'] = entity['name']
data
curl -H "X-API-Key: 47fda570" -X POST -d '{"name":"random_POSTname"}' https://my.api.mockaroo.com/v2.json
and Instead of getting name: "random_POSTname" I'm getting response:
{"id":1,"name":null}
Is "entity" option working correctly?
I don't have experience with the v2 version of the interface, so I can only provide you an answer for the methods described at the API documentation page.
What I noticed is that {"id":1,"name":null} is always the default output, so there is something wrong in your request.
I do not know which operating system you are using, but you can not use single quotes in windows (command prompt) to surround a parameter.
Also try to understand the API reference, because this is not how the parameters work: You have to provide a JSON array with n objects each containing at least a name attribute and a type attribute.
What I did to make it work in your case is:
1. use the "old" api
2. Provide an Array
3. Add an object with name=name, type=Blank, formula="random_POSTname"
With the double quote escaping of the Windows command line, it gets a bit messy, so please consider using a file as data instead of cmd parameters.
Solution:curl "https://api.mockaroo.com/api/generate.json?key={{YOUR_API_KEY}}&count=5" -d "[{"""name""":"""name""","""type""":"""Blank""","""formula""":"""'random_POSTname'"""}]"
Please change {{YOUR_API_KEY}} with the relevant value (maybe you want to remove it from your original question too, to prevent abuse).
When you are creating the email you can choose the Alphabetic or numeric values. you can also use the Roadrunner email for better email services. for instant support related to the Roadrunner Email please contact Roadrunner Email Error 0x800ccc90 for the proper solution.
Bump Bump... not hearing back from Mark. Is this a dead service?
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Note: this fails for CSV, but works for json...
I'm trying to create an array of strings. I choose Custom List and give it values of "Task, File, Note, Appt"
If I call the field registrations[], it will populate with a single value.
If i call the field registrations[1-2], it always ends up empty
I do exactly as described here but it does not work - https://mockaroo.com/ff6a9e90
I am receiving a field not found error for an email field. If I switch the field in the formula to the Id field, everything works as expected.
You can use a Formula field and enter this formula. It does behave a bit differently, but it solves your case for CSVs if you want to have one column with multiple random values in a comma separated list.
'Task,File,Note,Appt'.split(',').sample(random(1,4)).join(', ')
Can you update your sample schema link?
The page you are looking for does not exist.
There is a 'Share Link:' at the bottom of your schema you need to use, not the url of the schema.
I will recommend you to use Total CSV Converter tool developed by COOLUTIL company. This tool is used to convert CSV and TSV files into DOC, PDF, JSON nd many more. Software comes in two variants Paid and Free. I will personally recommend you to go with free version at first.
mockaroo - is this going to be available soon?
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It looks like it has something to do with the relation between email and first name (you'll see that the initial/name in the email and first name are the same). This is causing some kind of bug. When we change the field to something unrelated, there is no problem in the execution.
I found a workaround by adding a dummy First Name field after the initial First Name field. Prepend it with underscores so it won't show up in your data:
